x^2-68x+867=0

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Solution for x^2-68x+867=0 equation:



x^2-68x+867=0
a = 1; b = -68; c = +867;
Δ = b2-4ac
Δ = -682-4·1·867
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-34}{2*1}=\frac{34}{2} =17 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+34}{2*1}=\frac{102}{2} =51 $

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